Python 3.11+
The examples use the standard Python syntax and containers supported by the browser Judge; the Prefix Sum invariant is independent of a minor Python release.
Verify in Python docs(opens in a new tab)Precompute cumulative aggregates so range queries become constant-time differences. Learn its decision rule, maintained state, Python cost model, and transfer from a focused drill to a full Interview Problem.
Recognize it when
Consider Prefix Sum when the prompt's constraints and required operations match this shape: Precompute cumulative aggregates so range queries become constant-time differences.

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prefix[i] stores the aggregate of the first i values. The leading identity at boundary zero describes the empty prefix and makes every input position correspond to the gap immediately after it.
A half-open range [left, right) has sum prefix[right] - prefix[left]. This single formula covers empty ranges and ranges beginning at zero, avoiding left - 1 branches and off-by-one special cases.
def build_prefix_aggregates(values):
prefix = [0]
for value in values:
prefix.append(prefix[-1] + value)
return prefixImplement build_prefix_aggregates(values). Return length n + 1 with prefix[0] = 0 and prefix[i + 1] including values[i].
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Two boundaries summarize any immutable subarray in O(1). For target-sum counting, rearrange current_prefix - earlier_prefix = target and store frequencies of earlier prefixes in a hash map.
def range_sum_queries(values, queries):
prefix = [0]
for value in values:
prefix.append(prefix[-1] + value)
return [prefix[right] - prefix[left] for left, right in queries]Implement range_sum_queries(values, queries). Each query is a half-open [left, right] range. Return its sum.
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Use prefix sums for many immutable range queries, arbitrary signed values, or prefix-frequency equations. Use a sliding window when validity changes monotonically as a contiguous boundary moves. Building prefixes costs O(n) time and space; each direct range query is O(1).
Say: “prefix[i] is the sum before index i, so subtracting two boundaries cancels everything outside the range.” Trace a range beginning at zero and an empty range. Binary Subarrays With Sum(opens in a new tab) adds a frequency map to the same difference identity.
Python 3.11+
The examples use the standard Python syntax and containers supported by the browser Judge; the Prefix Sum invariant is independent of a minor Python release.
Verify in Python docs(opens in a new tab)Interview bounds depend on the stated representation, input model, and real Python operations.
| Operation | Average | Worst | Interview note |
|---|---|---|---|
| Prefix Sum decision loop | O(n) | O(n) | Repeated range totals become simple differences when one cumulative boundary value is stored before every input position. After consuming i values, the final aggregate equals sum(values[:i]) and the list has i + 1 entries. |
O(n) for the focused Build Prefix Aggregates implementation.
These are the mistakes most likely to survive a happy-path example and fail a boundary case.
Applying the pattern without proving its ordering, monotonicity, or window invariant can silently miss valid candidates.
Prevent it: Write the decision rule beside the loop and verify it against Build Prefix Aggregates before optimizing.
Avoid
def build_prefix_aggregates(values):
passUse instead
def build_prefix_aggregates(values):
prefix = [0]
for value in values:
prefix.append(prefix[-1] + value)
return prefixWhere you will hit this: Build Prefix Aggregates(opens in a new tab)
Omits the leading zero boundary, shifting every range endpoint and returning the wrong required length.
Prevent it: Use the public tests and preserve this state: prefix[i] summarizes exactly the first i values.
Avoid
def build_prefix_aggregates(values):
prefix = []
total = 0
for value in values:
total += value
prefix.append(total)
return prefixUse instead
def build_prefix_aggregates(values):
prefix = [0]
for value in values:
prefix.append(prefix[-1] + value)
return prefixWhere you will hit this: Build Prefix Aggregates(opens in a new tab)
Python slicing, copying, membership in lists, or repeated sorting inside the loop can invalidate the intended complexity.
Prevent it: Count every slice, copy, sort, membership check, and container update before claiming O(n).
Avoid
def build_prefix_aggregates(values):
prefix = []
total = 0
for value in values:
total += value
prefix.append(total)
return prefixUse instead
def build_prefix_aggregates(values):
prefix = [0]
for value in values:
prefix.append(prefix[-1] + value)
return prefixWhere you will hit this: Binary Subarrays With Sum(opens in a new tab)
Official Python documentation supports language behavior. Canonical problem pages provide additional practice context.
python-docs · checked 2026-07-27