Python 3.11+
The code uses standard Python syntax and containers supported by the browser Judge. The Radix Sort proof does not depend on a minor Python release.
Verify in Python docs(opens in a new tab)Apply stable digit-wise passes to sort bounded-width keys without direct comparisons. Learn the algorithm's preconditions, state transition, correctness argument, Python cost model, and transfer from one focused drill to a full Interview Problem.
Recognize it when
Consider Radix Sort when the prompt's constraints and required operations match this shape: Apply stable digit-wise passes to sort bounded-width keys without direct comparisons.

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Radix sort orders keys by repeated digit passes rather than pairwise comparison. Least-significant-digit sorting begins at the lowest place and preserves earlier digit work through stability.
Items sharing the current digit must retain their prior relative order. Stable buckets or counting placement ensures higher-place passes do not destroy the ordering already established by lower places.
def radix_pass_trace(values):
output=values.copy();trace=[];place=1;maximum=max(output,default=0)
while maximum//place:
buckets=[[] for _ in range(10)]
for value in output:buckets[(value//place)%10].append(value)
output=[value for bucket in buckets for value in bucket];trace.append(output.copy());place*=10
return traceImplement radix_pass_trace(values). For nonnegative integers, return the list after each stable base-10 digit pass.
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With base b and d digits, work is O(d(n + b)). A larger base reduces passes but increases bucket memory; count passes from the maximum key representation.
def radix_sort(values):
output=values.copy();place=1;maximum=max(output,default=0)
while maximum//place:
buckets=[[] for _ in range(10)]
for value in output:buckets[(value//place)%10].append(value)
output=[value for bucket in buckets for value in bucket];place*=10
return outputImplement radix_sort(values). Return a sorted copy of nonnegative integers using stable base-10 passes.
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Missing higher digits act as zero for nonnegative integers. Signed values need a deliberate strategy such as separately sorting magnitudes of negatives and reversing their order; direct digit extraction alone is insufficient.
Say: “Each stable digit pass refines order without breaking lower-place ties. After every digit of the maximum key, full numeric order is established.” State base, sign domain, stability, and O(d(n + b)) cost.
Python 3.11+
The code uses standard Python syntax and containers supported by the browser Judge. The Radix Sort proof does not depend on a minor Python release.
Verify in Python docs(opens in a new tab)Interview bounds depend on the stated representation, input model, and real Python operations.
| Operation | Average | Worst | Interview note |
|---|---|---|---|
| Radix Sort complete workflow | O(d(n + 10)) | O(d(n + 10)) | Perform stable base-10 bucket passes from the least significant digit through the maximum value. |
O(n + 10) for the focused Sort Nonnegative Integers by Digits implementation.
These are the mistakes most likely to survive a happy-path example and fail a boundary case.
Verify algorithm preconditions such as sorted input, nonnegative weights, acyclicity, or admissible heuristics before applying it.
Prevent it: State and verify this precondition before coding: The comparison, key domain, stability need, and memory constraints match the selected ordering method.
Avoid
def radix_sort(values):
passUse instead
def radix_sort(values):
result = list(values)
if not result:
return result
place = 1
maximum = max(result)
while place <= maximum:
buckets = [[] for _ in range(10)]
for value in result:
buckets[(value // place) % 10].append(value)
result = [value for bucket in buckets for value in bucket]
place *= 10
return resultWhere you will hit this: Sort Nonnegative Integers by Digits(opens in a new tab)
Runs only the ones-place pass and fails on multiple-digit values.
Prevent it: Preserve this proof obligation: The resolved prefix, suffix, rank, digit pass, or bucket remains in its documented final relation.
Avoid
def radix_sort(values):
buckets=[[] for _ in range(10)]
for value in values:buckets[value%10].append(value)
return [x for bucket in buckets for x in bucket]Use instead
def radix_sort(values):
result = list(values)
if not result:
return result
place = 1
maximum = max(result)
while place <= maximum:
buckets = [[] for _ in range(10)]
for value in result:
buckets[(value // place) % 10].append(value)
result = [value for bucket in buckets for value in bucket]
place *= 10
return resultWhere you will hit this: Sort Nonnegative Integers by Digits(opens in a new tab)
Include visited state, boundary cases, recursion depth, and hidden copying costs in correctness and complexity analysis.
Prevent it: Count every sort, slice, copy, membership check, heap update, and recursive frame before claiming O(d(n + 10)).
Avoid
def radix_sort(values):
buckets=[[] for _ in range(10)]
for value in values:buckets[value%10].append(value)
return [x for bucket in buckets for x in bucket]Use instead
def radix_sort(values):
result = list(values)
if not result:
return result
place = 1
maximum = max(result)
while place <= maximum:
buckets = [[] for _ in range(10)]
for value in result:
buckets[(value // place) % 10].append(value)
result = [value for bucket in buckets for value in bucket]
place *= 10
return resultWhere you will hit this: Car Fleet(opens in a new tab)
Official Python documentation supports language behavior. Canonical problem pages provide additional practice context.
python-docs · checked 2026-07-27