Python 3.11+
The code uses standard Python syntax and containers supported by the browser Judge. The Fisher-Yates Shuffle proof does not depend on a minor Python release.
Verify in Python docs(opens in a new tab)Generate an unbiased permutation by swapping each position with a uniformly chosen remaining one. Learn the algorithm's preconditions, state transition, correctness argument, Python cost model, and transfer from one focused drill to a full Interview Problem.
Recognize it when
Consider Fisher-Yates Shuffle when the prompt's constraints and required operations match this shape: Generate an unbiased permutation by swapping each position with a uniformly chosen remaining one.

Sign in to save your code and progress across devices. The lesson and problem statement remain public.
Fisher-Yates processes positions from the end toward the front. For position i, it chooses uniformly from every index zero through i that has not yet been finalized.
Swap the chosen item into position i, then never touch that suffix position again. The remaining prefix contains exactly the items still available for earlier positions.
def shuffle_trace(values,draws):
values=values.copy();trace=[]
for offset,index in enumerate(range(len(values)-1,0,-1)):
chosen=draws[offset];values[index],values[chosen]=values[chosen],values[index];trace.append([index,chosen,values.copy()])
return traceImplement shuffle_trace(values,draws). Moving right to left, draws provides j in [0,i]; return [i,j,state] after each swap.
Loading interactive editor.If it does not appear, the reference and starter code remain readable.Reload editor
The draw must include both zero and i. Excluding i or choosing from the entire array each time makes permutation probabilities unequal.
def shuffled(values,draws):
output=values.copy()
for offset,index in enumerate(range(len(output)-1,0,-1)):
chosen=draws[offset];output[index],output[chosen]=output[chosen],output[index]
return outputImplement shuffled(values,draws). Return a shuffled copy using supplied inclusive draws.
Loading interactive editor.If it does not appear, the reference and starter code remain readable.Reload editor
Classic Fisher-Yates mutates in place with O(1) auxiliary space. Copy first when caller input must remain unchanged, and inject the random source or draws for deterministic tests.
Say: “At step i, each remaining item has equal probability of taking final position i. One uniform inclusive draw and swap finalizes it.” State O(n) time, mutation policy, RNG quality, and why repeated arbitrary swaps are biased.
Python 3.11+
The code uses standard Python syntax and containers supported by the browser Judge. The Fisher-Yates Shuffle proof does not depend on a minor Python release.
Verify in Python docs(opens in a new tab)Interview bounds depend on the stated representation, input model, and real Python operations.
| Operation | Average | Worst | Interview note |
|---|---|---|---|
| Fisher-Yates Shuffle complete workflow | O(n) | O(n) | Copy the input and perform the supplied Fisher-Yates swap for every shrinking suffix boundary. |
O(n) for the focused Simulate Fisher-Yates Shuffling implementation.
These are the mistakes most likely to survive a happy-path example and fail a boundary case.
Verify algorithm preconditions such as sorted input, nonnegative weights, acyclicity, or admissible heuristics before applying it.
Prevent it: State and verify this precondition before coding: Each random choice is uniform over the documented candidate range and uses an unbiased random source.
Avoid
def fisher_yates(values, choices):
passUse instead
def fisher_yates(values, choices):
shuffled = list(values)
for offset, index in enumerate(range(len(shuffled) - 1, 0, -1)):
choice = choices[offset]
shuffled[index], shuffled[choice] = shuffled[choice], shuffled[index]
return shuffledWhere you will hit this: Simulate Fisher-Yates Shuffling(opens in a new tab)
Returns the input order and ignores deterministic swap choices.
Prevent it: Preserve this proof obligation: Induction shows each eligible item or permutation retains the required equal probability after every update.
Avoid
def fisher_yates(values,choices):
return list(values)Use instead
def fisher_yates(values, choices):
shuffled = list(values)
for offset, index in enumerate(range(len(shuffled) - 1, 0, -1)):
choice = choices[offset]
shuffled[index], shuffled[choice] = shuffled[choice], shuffled[index]
return shuffledWhere you will hit this: Simulate Fisher-Yates Shuffling(opens in a new tab)
Include visited state, boundary cases, recursion depth, and hidden copying costs in correctness and complexity analysis.
Prevent it: Count every sort, slice, copy, membership check, heap update, and recursive frame before claiming O(n).
Avoid
def fisher_yates(values,choices):
return list(values)Use instead
def fisher_yates(values, choices):
shuffled = list(values)
for offset, index in enumerate(range(len(shuffled) - 1, 0, -1)):
choice = choices[offset]
shuffled[index], shuffled[choice] = shuffled[choice], shuffled[index]
return shuffledWhere you will hit this: Shortest Subarray With OR at Least K(opens in a new tab)
Official Python documentation supports language behavior. Canonical problem pages provide additional practice context.
python-docs · checked 2026-07-27